Unknown
On Minggu, 11 November 2012
(experimental) or real results
the theoretical result of equation multiplied
one hundred percent.
Real Results
% Result = x 100%
Theoretical Results
Concrete results are usually smaller than the theoretical yield.
example 2.10
If 68.5 g of carbon in the air
a. What is the theoretical yield of CO2 generated.
b. If the experiment produces CO2 237 g CO2
what is the% yield
completion
a. Reaction: C (p) + O2 (g) CO2 (g)
moles C = 68.4 g/12 g mol-1 = 5.7 mol
mol CO2 = 5.7 mol
mass of CO2 = 5.7 mol x 44 g mol-1 = 250.8 g
Real Results
b. % Yield = x 100%
Theoretical Results
237 g CO = 2 x 100% = 94.5%
250.8 g CO2
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